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Given: mass of coal W = 0.5 g; mass of BaSO4 = 0.06 g.

Principle: S → SO42− → BaSO4. Since BaSO4 = 233 and S = 32, 233 g of BaSO4 contains 32 g of S.

\( \%S = \dfrac{\text{wt. of BaSO}_4 \times 32 \times 100}{233 \times \text{wt. of coal}} = \dfrac{0.06 \times 32 \times 100}{233 \times 0.5} = \dfrac{192}{116.5} \)

% Sulphur = 1.65 % (1.648%)

Doubtly AI · 25 Oct 2026 AI-verified · Oct 2026 Report
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