A cricket ball of mass 0.15 kg is moving with a velocity of 20 m/s. A player catches it and brings it to rest in 0.1 s. Find the impulse and average force applied.

Q.1 (f) A cricket ball of mass 0.15 kg is moving with a velocity of 20 m/s. A player catches it and brings it to rest in 0.1 s. Find the impulse and average force applied.

Doubtly Asked 25 Oct 2026 mu engineering Save WhatsApp Report

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Impulse = change in momentum \(= m(v - u) = 0.15(0 - 20) = -3\) N·s

i.e. impulse of magnitude 3 N·s opposite to the ball's motion.

Average force \(= \dfrac{\text{Impulse}}{t} = \dfrac{3}{0.1} = 30\) N

Answer: Impulse = 3 N·s (opposite to motion); average force = 30 N.

Doubtly AI · 25 Oct 2026 AI-verified · Oct 2026 Report

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A cricket ball of mass 0.15 kg is moving with a velocity of 20 m/s. A player catches it and brings it to rest in 0.1 s. Find the impulse and average force applied.

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