Find the current through 8 Ω resistance using Thevenin's Theorem. [Circuit diagram: printed as an almost completely black (over-darkened) box in the source scan; element values and connections cannot be read — partly illegible in the source scan.]

Note: the circuit for this question is illegible in the source scan, so the numerical answer cannot be computed here. The complete Thevenin procedure the examiner expects is given below; apply it to the circuit printed in the paper.

1. Remove the load (the 8 Ω resistor) and label its terminals A and B.
2. Find V_th = open-circuit voltage V_AB using KVL/mesh, nodal analysis, voltage division or source transformation on the remaining circuit.
3. Find R_th: replace every independent voltage source by a short circuit and every independent current source by an open circuit (keeping internal resistances), and compute the equivalent resistance seen from A–B (series/parallel or star–delta).
4. Draw the Thevenin equivalent: V_th in series with R_th, and reconnect the 8 Ω across A–B.
5. Load current: \[ I_{8\Omega} = \frac{V_{th}}{R_{th} + 8} \] with direction from the + terminal of V_th through the 8 Ω.

      R_th
  +--/\/\/--+---- A
  |         |
 V_th      8 ohm   I = V_th / (R_th + 8)
  |         |
  +---------+---- B