What is the necessary condition for resonance in a series circuit? Derive an expression for resonance frequency.
Q.4 (c) What is the necessary condition for resonance in a series circuit? Derive an expression for resonance frequency.
Q.4 (c) What is the necessary condition for resonance in a series circuit? Derive an expression for resonance frequency.
Best answer
Condition: an R-L-C series circuit is at resonance when the inductive reactance equals the capacitive reactance, XL = XC. Then the net reactance is zero, impedance is minimum (Z = R), current is maximum (I = V/R) and in phase with the applied voltage (unity power factor).
Derivation: for a series R-L-C circuit, \( Z = R + j(X_L - X_C) = R + j\left(\omega L - \dfrac{1}{\omega C}\right) \).
At resonance the imaginary part is zero: \( \omega_rL = \dfrac{1}{\omega_rC} \Rightarrow \omega_r^2 = \dfrac{1}{LC} \Rightarrow \omega_r = \dfrac{1}{\sqrt{LC}} \).
Since ωr = 2πfr: \[ \mathbf{f_r = \frac{1}{2\pi\sqrt{LC}}\ \text{Hz}} \]
I ^ _
| / \ I_max = V/R at f_r
| / \
| / \
| ___/ \___
+---------|----------> f
f_r
below f_r: capacitive (X_C > X_L); above f_r: inductive (X_L > X_C)
At resonance VL = VC = QV (voltage magnification), with \( Q = \dfrac{\omega_rL}{R} = \dfrac{1}{R}\sqrt{\dfrac{L}{C}} \); bandwidth = R/(2πL) = fr/Q.
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