In one line
The ICR is the point, in or outside the body, that has zero velocity at a given instant, so the body seems to rotate purely about it at that instant.
Explained simply
For a fraction of a second, any moving flat body looks as if it is spinning about one fixed pin. That imaginary pin is the instantaneous centre. A moment later it may be somewhere else, so it is 'instantaneous'.
Technically, in general plane motion, the velocity of any point P is \( v_P = \omega \cdot IP \), perpendicular to the line IP, where I is the ICR and \( \omega \) the body's angular velocity.
How it works
- Find two points A and B on the body whose velocity directions are known.
- Draw lines through A and B perpendicular to their velocities.
- Their intersection is the ICR, I.
- \( \omega = v_A / IA \); then \( v_B = \omega \cdot IB \), direction perpendicular to IB.
- Use geometry (sine rule or right triangles) to get IA and IB.
- Special cases: rolling without slip: I is the contact point; if the perpendiculars are parallel (velocities parallel and equal), I is at infinity and the body is momentarily translating (\( \omega = 0 \)).
Key formula
\( \omega = \dfrac{v_A}{IA} = \dfrac{v_B}{IB} \); v in m/s, distances in m, \( \omega \) in rad/s.
Quick example
A 5 m rod AB slides with A on the floor and B on a wall, at 30° to the floor; A moves away from the wall at 2 m/s. Perpendiculars meet at I, where IA = \( 5\sin30^\circ = 2.5 \) m and IB = \( 5\cos30^\circ = 4.33 \) m. \( \omega = 2/2.5 = 0.8 \) rad/s; \( v_B = 0.8 \times 4.33 = 3.46 \) m/s downward.
Common mistakes
- Drawing lines along the velocities instead of perpendicular to them.
- Using ICR to find accelerations; the ICR generally has non-zero acceleration, so the method is only for velocities.
- Using the rod length instead of the distance from I.
How MU asks it
Theory 3 to 4 marks: 'Define the ICR and explain how to locate it'. Numerical 6 to 8 marks: sliding rods, ladders, rolling wheels, two-link mechanisms (syllabus limits to 2 links, no relative velocity method). Draw the configuration to scale-like proportions, mark I, show the geometry for IA and IB.