Skip to content
doubtly

1 answer

In one line

By measuring the diameters of two dark rings that are \(p\) rings apart and knowing the lens radius \(R\), the wavelength is found from \(\lambda = (D_{n+p}^2 - D_n^2)/(4pR)\).

Explained simply

The ring sizes depend on the wavelength of light: longer waves make bigger rings. So if you measure ring sizes accurately with a microscope, you can work backwards to find the wavelength. Using a difference of two rings cancels errors from dust or imperfect contact at the centre.

How it works

  1. Set up Newton's rings with an air film (\(\mu = 1\)) and the given monochromatic source.
  2. Using a travelling microscope, measure diameters \(D_n\) and \(D_{n+p}\) of the \(n\)th and \((n+p)\)th dark rings (take readings on both sides of centre and subtract).
  3. From \(D_n^2 = 4n\lambda R\) and \(D_{n+p}^2 = 4(n+p)\lambda R\), subtract: \(D_{n+p}^2 - D_n^2 = 4p\lambda R\).
  4. So \(\lambda = \dfrac{D_{n+p}^2 - D_n^2}{4pR}\).
  5. Find \(R\) of the lens with a spherometer. Plotting \(D_n^2\) against \(n\) gives a straight line with slope \(4\lambda R\), which averages many readings.
  6. The difference method is used because the exact centre may not be a perfect point (dust, lens pressure), which shifts all \(D_n^2\) by the same amount; subtracting removes this error.

Key formula

\(\lambda = \dfrac{D_{n+p}^2 - D_n^2}{4pR}\). \(D_{n+p}, D_n\): diameters of the \((n+p)\)th and \(n\)th dark rings (m), \(p\): number of rings between them, \(R\): radius of curvature (m), \(\lambda\) in m.

Quick example

Sample reading: \(D_{15} = 0.590\) cm, \(D_5 = 0.336\) cm, \(p = 10\), \(R = 100\) cm. \(D_{15}^2 - D_5^2 = 0.3481 - 0.1129 = 0.2352\) cm2. \(\lambda = 0.2352/(4\times10\times100) = 5.88\times10^{-5}\) cm = 588 nm, close to sodium light.

Common mistakes

  • Using radii in a formula written for diameters (or the reverse), giving an error of a factor of 4.
  • Mixing cm and m within one calculation.
  • Taking \(p\) as \(n+p\) instead of the difference in ring numbers.

How MU asks it

Asked as "Explain how Newton's rings are used to determine wavelength of light" (5 marks) and very often as a numerical (3 to 5 marks). Write the set-up briefly, derive \(D_{n+p}^2 - D_n^2 = 4p\lambda R\), and in numericals keep units consistent and give \(\lambda\) in nm or Å.

Doubtly AI · 25 Oct 2026 AI-verified · Oct 2026 Report
Was this answer helpful?

Your answer

Log in or create a free account to answer this question.