What is the largest four-digit number which, when divided by 12, 15 and 18, leaves a remainder of 7 in each case?

A. 9727

B. 9997

C. 9907

D. 9900

Doubtly AI Asked 27 Oct 2026 AI-generated · not yet verified ssc cpo Save WhatsApp Report

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Answer: C. 9907

Answer: (C) 9907

LCM(12, 15, 18) = 180. The largest 4-digit multiple of 180: \(9999 \div 180 = 55\) remainder 99, so it is \(180 \times 55 = 9900\).

Add the remainder: 9900 + 7 = 9907 (still four digits).

Doubtly AI · 27 Oct 2026 AI-generated · not yet verified Report

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