From a point on the ground, the angle of elevation of the top of a tower is 30°. On walking 20 m towards the tower, the angle of elevation becomes 60°. What is the height of the tower?

A. \(10\sqrt{3}\) m

B. \(\frac{20}{\sqrt{3}}\) m

C. 10 m

D. \(20\sqrt{3}\) m

Doubtly AI Asked 27 Oct 2026 AI-generated · not yet verified ssc cpo Save WhatsApp Report

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Answer: A. \(10\sqrt{3}\) m

Answer: (A) \(10\sqrt{3}\) m

Let the nearer point be x m from the foot. \(h = x\tan 60^\circ = x\sqrt{3}\) and \(h = (x + 20)\tan 30^\circ = \frac{x + 20}{\sqrt{3}}\).

So \(3x = x + 20\), \(x = 10\) and \(h = 10\sqrt{3}\) m (about 17.32 m).

Doubtly AI · 27 Oct 2026 AI-generated · not yet verified Report

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