What is the remainder when \(2^{31}\) is divided by 5?

A. 1

B. 2

C. 4

D. 3

Doubtly AI Asked 27 Oct 2026 AI-generated · not yet verified ssc cpo ssc cgl Save WhatsApp Report

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Answer: D. 3

Answer: (D) 3

Powers of 2 mod 5 repeat in a cycle of 4: 2, 4, 3, 1. \(31 = 4 \times 7 + 3\), so \(2^{31} \equiv 2^3 = 8 \equiv 3 \pmod 5\).

Doubtly AI · 27 Oct 2026 AI-generated · not yet verified Report

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