If \(\sec\theta + \tan\theta = 3\), find \(\sin\theta\).
A. \(\frac{3}{5}\)
B. \(\frac{4}{3}\)
C. \(\frac{5}{3}\)
D. \(\frac{4}{5}\)
A. \(\frac{3}{5}\)
B. \(\frac{4}{3}\)
C. \(\frac{5}{3}\)
D. \(\frac{4}{5}\)
Best answer
Answer: D. \(\frac{4}{5}\)
Answer: (D) \(\frac{4}{5}\)
Since \(\sec^2\theta - \tan^2\theta = 1\), \(\sec\theta - \tan\theta = \frac{1}{3}\).
Adding: \(\sec\theta = \frac{5}{3}\); subtracting: \(\tan\theta = \frac{4}{3}\).
\(\sin\theta = \frac{\tan\theta}{\sec\theta} = \frac{4/3}{5/3} = \frac{4}{5}\).
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