What is the area of the circle inscribed in an equilateral triangle of side 12 cm?
A. \(6\pi\) cm²
B. \(12\pi\) cm²
C. \(36\pi\) cm²
D. \(48\pi\) cm²
A. \(6\pi\) cm²
B. \(12\pi\) cm²
C. \(36\pi\) cm²
D. \(48\pi\) cm²
Best answer
Answer: B. \(12\pi\) cm²
Answer: (B) \(12\pi\) cm²
Inradius of an equilateral triangle = \(\frac{a}{2\sqrt{3}} = \frac{12}{2\sqrt{3}} = 2\sqrt{3}\) cm.
Area = \(\pi (2\sqrt{3})^2 = 12\pi\) cm².
Trap: \(48\pi\) uses the circumradius \(\frac{a}{\sqrt{3}} = 4\sqrt{3}\).
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