\(49^{15} - 1\) is exactly divisible by which of the following?
A. 50
B. 51
C. 29
D. 48
A. 50
B. 51
C. 29
D. 48
Best answer
Answer: D. 48
Answer: (D) 48
\(a^n - b^n\) is always divisible by \(a - b\). So \(49^{15} - 1^{15}\) is divisible by 49 − 1 = 48.
50 = 49 + 1 divides it only when the power is even; 15 is odd.
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