A boy walking at 5 km/h reaches school 7 minutes late. Walking at 6 km/h he reaches 5 minutes early. How far is the school?
A. 6.5 km
B. 7.5 km
C. 6 km
D. 5 km
A. 6.5 km
B. 7.5 km
C. 6 km
D. 5 km
Best answer
Answer: C. 6 km
Answer: (C) 6 km
The difference in time = 7 + 5 = 12 min = \(\frac{1}{5}\) h.
Shortcut: \(d = \frac{S_1 S_2}{S_2 - S_1} \times \text{time difference} = \frac{5 \times 6}{1} \times \frac{1}{5} = 6\) km.
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