A train is running 20 minutes late. By increasing its speed by 16 km/h it covers the next 160 km and arrives on time. What is its usual speed?
A. 80 km/h
B. 64 km/h
C. 96 km/h
D. 72 km/h
A. 80 km/h
B. 64 km/h
C. 96 km/h
D. 72 km/h
Best answer
Answer: A. 80 km/h
Answer: (A) 80 km/h
\(\frac{160}{v} - \frac{160}{v + 16} = \frac{1}{3}\), so v(v + 16) = 160 × 16 × 3 = 7680.
80 × 96 = 7680, so v = 80 km/h. (Check with options: only 80 fits.)
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