The sum of the present ages of a father and his son is 56 years. Four years ago, the father's age was three times the son's age. What is the father's present age (in years)?
A. 36
B. 40
C. 42
D. 44
A. 36
B. 40
C. 42
D. 44
Best answer
Answer: B. 40
Answer: (B) 40
F + S = 56 and F − 4 = 3(S − 4), so F = 3S − 8. Then 4S − 8 = 56, S = 16 and F = 40 years.
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