The population of a town increased by 10% in the first year and decreased by 10% in the second year. If the population at the end of the second year is 39,600, what was it at the beginning of the first year?
A. 40,000
B. 41,000
C. 38,000
D. 39,600
A. 40,000
B. 41,000
C. 38,000
D. 39,600
Best answer
Answer: A. 40,000
Answer: (A) 40,000
\(P \times 1.1 \times 0.9 = 0.99P = 39600\), so \(P = 40000\). (A 10% rise followed by a 10% fall is a net 1% fall.)
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