What is the least number which, when divided by 12, 15, 20 and 54, leaves a remainder of 8 in each case?
A. 548
B. 532
C. 540
D. 1088
1 answer
Best answer
Answer: A. 548
Answer: (A) 548
LCM(12, 15, 20, 54) = 540. Required number \(= 540 + 8 = 548\).
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· 27 Oct 2026
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