Energy of H-atom in the ground state is –13.6 eV, hence energy in the second excited state is

Energy of H-atom in the ground state is –13.6 eV, hence energy in the second excited state is
(a) –6.8 eV (b) -3.4 eV (c) –1.51 eV (d) –4.53 eV

Doubtly Asked 25 May 2021 structure-of-atom Save WhatsApp Report

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Best answer

Correct answer is option (c) –1.51 eV

Explaination::

\(2 ^{nd}\ excited \ state \ n=3 E n =− \frac{ 13.06}{n^2} \) -{By formula }

\(E_3=-\frac{13.06}{3^2}=-\frac{13.06}{9}\)

= -1.51 eV

Doubtly · 25 May 2021 Report

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