The r.m.s. speed of the molecules of a gas at 27 °C is \(v\). The temperature at which the r.m.s. speed becomes \(2v\) is
A. 108 °C
B. 1200 °C
C. 327 °C
D. 927 °C
1 answer
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Answer: D. 927 °C
\(v_{rms}\propto\sqrt{T}\): \(T_2=4\times300=1200\) K \(=927\) °C.
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· 23 Oct 2026
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