A Carnot engine has efficiency 40% with its sink at 300 K. Keeping the sink temperature constant, by how much should the source temperature be increased to raise the efficiency to 50%?
A. 50 K
B. 200 K
C. 100 K
D. 150 K
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Answer: C. 100 K
\(0.4=1-\frac{300}{T_1}\Rightarrow T_1=500\) K. For 50%: \(T_1'=600\) K. Increase \(=100\) K.
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· 23 Oct 2026
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