In Young's double slit experiment, slit separation is 0.5 mm, the screen is 1 m away and \(\lambda=600\) nm. The fringe width is
A. 1.2 mm
B. 0.12 mm
C. 0.6 mm
D. 2.4 mm
1 answer
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Answer: A. 1.2 mm
\(\beta=\frac{\lambda D}{d}=\frac{600\times10^{-9}\times1}{0.5\times10^{-3}}=1.2\times10^{-3}\) m.
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· 23 Oct 2026
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