The de Broglie wavelength of an electron accelerated from rest through a potential difference of 100 V is about
A. 0.1227 Å
B. 1.227 Å
C. 0.388 Å
D. 12.27 Å
1 answer
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Answer: B. 1.227 Å
\(\lambda=\frac{12.27}{\sqrt V}\) Å \(=\frac{12.27}{10}=1.227\) Å.
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· 23 Oct 2026
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