A projectile is fired so that its horizontal range equals its maximum height. The angle of projection with the horizontal is
A. 45°
B. \(\tan^{-1}\left(\frac14\right)\)
C. \(\tan^{-1}(4)\)
D. \(\tan^{-1}(2)\)
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Answer: C. \(\tan^{-1}(4)\)
\(\frac{2u^2\sin\theta\cos\theta}{g}=\frac{u^2\sin^2\theta}{2g}\Rightarrow\tan\theta=4\).
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· 23 Oct 2026
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