A planet has the same mean density as the earth but twice its radius. If the escape speed on earth is 11.2 km/s, the escape speed on the planet is
A. 22.4 km/s
B. 44.8 km/s
C. 11.2 km/s
D. 15.8 km/s
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Answer: A. 22.4 km/s
\(v_e=\sqrt{\frac{2GM}{R}}=R\sqrt{\frac{8\pi G\rho}{3}}\propto R\) for equal density, so \(2\times11.2=22.4\) km/s.
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· 23 Oct 2026
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