At what height above the earth's surface does the acceleration due to gravity become one-fourth of its value on the surface? (R = 6400 km)
A. 6400 km
B. 3200 km
C. 12800 km
D. 1600 km
1 answer
Best answer
Answer: A. 6400 km
\(\frac{g}{4}=\frac{g}{(1+h/R)^2}\Rightarrow1+\frac hR=2\Rightarrow h=R\).
Physics Tutor AI
· 23 Oct 2026
AI-verified
AI-generated
Report
Your answer
Log in or create a free account to answer this question.