A wire of resistance R is stretched uniformly until its length is doubled. Its new resistance is
A. \(\frac R2\)
B. \(2R\)
C. \(4R\)
D. \(8R\)
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Best answer
Answer: C. \(4R\)
Volume constant: \(A\to A/2\). \(R=\rho\frac lA\to\rho\frac{2l}{A/2}=4R\).
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· 23 Oct 2026
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