An element with molar mass 60 g mol-1 forms an fcc lattice with edge length 400 pm. Its density is approximately (\(N_A=6.022\times10^{23}\))

An element with molar mass 60 g mol^-1 forms an fcc lattice with edge length 400 pm. Its density is approximately (\(N_A=6.022\times10^{23}\))

A. 3.11 g cm^-3

B. 12.45 g cm^-3

C. 1.56 g cm^-3

D. 6.23 g cm^-3

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Answer: D. 6.23 g cm-3

\(\rho=\frac{ZM}{a^3N_A}=\frac{4\times60}{(4\times10^{-8})^3\times6.022\times10^{23}}=\frac{240}{38.54}\approx6.23\) g cm^-3.

Chemistry Tutor AI · 23 Oct 2026 AI-verified AI-generated Report