Let A={θϵ(-π/2π):3+2isinθ/1-2isinθ is purely imaginary} then the sum of elements in A is
\(A={θϵ}({-π\over2},π):{{3+2i\sin\theta}\over 1-2i\sin\theta}\)
A)\(3π\over4\)
B)\(5π\over6\)
C)\(π\)
D)\(2π\over3\)
1 answer
Best answer
The correct answer is D)2π/3
Detailed answer
Was this answer helpful?
Thanks for the feedback.
Sign up free to save answers and ask your own doubts
Your answer
Log in or create a free account to answer this question.