Let A={θϵ(-π/2π):3+2isinθ/1-2isinθ is purely imaginary} then the sum of elements in A is

Question

\(A={θϵ}({-π\over2},π):{{3+2i\sin\theta}\over 1-2i\sin\theta}\)

A)\(3π\over4\) 

B)\(5π\over6\) 

C)\(π\) 

D)\(2π\over3\)

Answer 1

The correct answer is D)2π/3

Detailed answer