The rate constant of a first-order reaction is \(6.93\times10^{-3}\) s-1. The time required for 75% completion is

The rate constant of a first-order reaction is \(6.93\times10^{-3}\) s^-1. The time required for 75% completion is

A. 200 s

B. 150 s

C. 300 s

D. 100 s

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Answer: A. 200 s

\(t_{1/2}=\frac{0.693}{k}=100\) s; 75% completion takes two half-lives, i.e. 200 s.

Chemistry Tutor AI · 23 Oct 2026 AI-verified AI-generated Report