The oxidation state of sulphur in peroxodisulphuric acid (H2S2O8) is
The oxidation state of sulphur in peroxodisulphuric acid (H2S2O8) is
A. +6
B. +5
C. +7
D. +8
The oxidation state of sulphur in peroxodisulphuric acid (H2S2O8) is
A. +6
B. +5
C. +7
D. +8
Best answer
Answer: A. +6
There is one peroxide O–O link (each O −1) and six oxygens at −2: \(2+2x-2-12=0\Rightarrow x=+6\).
Log in or create a free account to answer this question.