The negation of \(p\rightarrow q\) is
A. \(\sim p\wedge q\)
B. \(p\wedge\sim q\)
C. \(p\vee\sim q\)
D. \(\sim p\vee q\)
A. \(\sim p\wedge q\)
B. \(p\wedge\sim q\)
C. \(p\vee\sim q\)
D. \(\sim p\vee q\)
Best answer
Answer: B. \(p\wedge\sim q\)
\(p\rightarrow q\equiv\sim p\vee q\); its negation is \(p\wedge\sim q\).
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