The value of \(\tan^{-1}2+\tan^{-1}3\) is
A. \(\frac{\pi}{2}\)
B. \(-\frac{\pi}{4}\)
C. \(\frac{\pi}{4}\)
D. \(\frac{3\pi}{4}\)
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Answer: D. \(\frac{3\pi}{4}\)
Since \(2\cdot3>1\) and both are positive, the sum \(=\pi+\tan^{-1}\frac{2+3}{1-6}=\pi-\frac\pi4=\frac{3\pi}{4}\).
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· 23 Oct 2026
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