The joint equation of the lines through the origin perpendicular to the lines \(x^2-5xy+4y^2=0\) is
A. \(4x^2+5xy+y^2=0\)
B. \(4x^2-5xy+y^2=0\)
C. \(4x^2+5xy-y^2=0\)
D. \(x^2+5xy+4y^2=0\)
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Answer: A. \(4x^2+5xy+y^2=0\)
Given lines \((x-y)(x-4y)=0\) have slopes \(1,\frac14\). Perpendicular slopes \(-1,-4\): \((x+y)(4x+y)=0\).
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· 23 Oct 2026
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