If \(x^2+y^2=25\), then \(\frac{d^2y}{dx^2}\) at the point \((3,4)\) is
A. \(\frac{25}{64}\)
B. \(-\frac34\)
C. \(-\frac{5}{16}\)
D. \(-\frac{25}{64}\)
1 answer
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Answer: D. \(-\frac{25}{64}\)
\(y'=-\frac xy=-\frac34\); \(y''=-\frac{y-xy'}{y^2}=-\frac{4+9/4}{16}=-\frac{25}{64}\).
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· 23 Oct 2026
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