\(\int e^x\left(\frac1x-\frac1{x^2}\right)dx=\)
A. \(\frac{e^x}{x}+C\)
B. \(e^x\ln x+C\)
C. \(-\frac{e^x}{x}+C\)
D. \(\frac{e^x}{x^2}+C\)
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Best answer
Answer: A. \(\frac{e^x}{x}+C\)
Form \(\int e^x(f+f')dx=e^xf+C\) with \(f=\frac1x\).
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· 23 Oct 2026
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