\(\int\frac{dx}{1+e^x}=\)
A. \(x+\ln(1+e^x)+C\)
B. \(\ln(1+e^{-x})+C\)
C. \(x-\ln(1+e^x)+C\)
D. \(\ln(1+e^x)+C\)
A. \(x+\ln(1+e^x)+C\)
B. \(\ln(1+e^{-x})+C\)
C. \(x-\ln(1+e^x)+C\)
D. \(\ln(1+e^x)+C\)
Best answer
Answer: C. \(x-\ln(1+e^x)+C\)
\(\frac{1}{1+e^x}=1-\frac{e^x}{1+e^x}\); integrate term by term.
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