A fair coin is tossed 6 times. The probability of getting exactly 3 heads is
A. \(\frac12\)
B. \(\frac38\)
C. \(\frac{5}{16}\)
D. \(\frac{15}{64}\)
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Answer: C. \(\frac{5}{16}\)
\(\binom63\left(\frac12\right)^6=\frac{20}{64}=\frac5{16}\).
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· 23 Oct 2026
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