The distance between the parallel lines \(3x+4y=5\) and \(6x+8y=25\) is
A. \(\frac12\)
B. \(\frac32\)
C. 2
D. 4
A. \(\frac12\)
B. \(\frac32\)
C. 2
D. 4
Best answer
Answer: B. \(\frac32\)
Write the second as \(3x+4y=12.5\): \(d=\frac{|12.5-5|}{5}=1.5\).
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