The length of the latus rectum of the ellipse \(\frac{x^2}{25}+\frac{y^2}{16}=1\) is
A. \(\frac{32}{5}\)
B. \(\frac85\)
C. \(\frac{25}{2}\)
D. \(\frac{16}{5}\)
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Answer: A. \(\frac{32}{5}\)
\(\frac{2b^2}{a}=\frac{2\times16}{5}=\frac{32}{5}\).
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· 23 Oct 2026
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