\(\lim_{x\to0}\frac{1-\cos4x}{x^2}=\)
A. 16
B. 8
C. 4
D. 2
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Answer: B. 8
\(1-\cos4x=2\sin^22x\); \(\lim\frac{2\sin^22x}{x^2}=2\cdot4=8\).
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· 23 Oct 2026
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