In cyclic quadrilateral ABCD, \(\angle A = 75°\). Then \(\angle C = \)
A. 75°
B. 15°
C. 105°
D. 285°
A. 75°
B. 15°
C. 105°
D. 285°
Best answer
Answer: C. 105°
Opposite angles of a cyclic quadrilateral are supplementary: \(180° - 75° = 105°\).
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