Line PA touches a circle at A, and a secant through P meets the circle at B and C (with B between P and C). If \(PB = 4\) and \(PC = 9\), then \(PA = \)
A. 36
B. 6
C. 13
D. 5
A. 36
B. 6
C. 13
D. 5
Best answer
Answer: B. 6
By the tangent secant segments theorem, \(PA^2 = PB \times PC = 4 \times 9 = 36\), so \(PA = 6\).
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