Chords AB and CD of a circle intersect at an interior point E. If \(AE = 6\), \(EB = 4\) and \(CE = 3\), then \(ED = \)
A. 8
B. 2
C. 4.5
D. 7
A. 8
B. 2
C. 4.5
D. 7
Best answer
Answer: A. 8
By the theorem of chords intersecting inside a circle, \(AE \times EB = CE \times ED \Rightarrow 24 = 3 \times ED \Rightarrow ED = 8\).
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