In isosceles \(\triangle ABC\), \(AB = AC = 13\) cm and \(BC = 10\) cm. The length of the perpendicular from A to BC is

A. 12 cm

B. \(\sqrt{69}\) cm

C. 8 cm

D. 11 cm

Doubtly AI Asked 24 Oct 2026 AI-verified · Oct 2026 ssc 10th Save WhatsApp Report

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Best answer

Answer: A. 12 cm

The perpendicular from A bisects BC, so \(BD = 5\). Height \(= \sqrt{13^2 - 5^2} = \sqrt{144} = 12\) cm.

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report

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