\(\triangle ABC \sim \triangle PQR\) and \(AB : PQ = 2 : 3\). Then \(A(\triangle ABC) : A(\triangle PQR) = \)

A. 2 : 3

B. 3 : 2

C. 4 : 9

D. 9 : 4

Doubtly AI Asked 24 Oct 2026 AI-verified · Oct 2026 ssc 10th Save WhatsApp Report

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Answer: C. 4 : 9

The ratio of the areas of similar triangles equals the ratio of the squares of corresponding sides: \(2^2 : 3^2 = 4 : 9\).

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report

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