In \(\triangle ABC\), seg \(DE \parallel\) side \(BC\), with D on AB and E on AC. If \(AD = 4\), \(DB = 6\) and \(AE = 6\), then \(EC = \)
A. 4
B. 6
C. 9
D. 12
A. 4
B. 6
C. 9
D. 12
Best answer
Answer: C. 9
By the basic proportionality theorem, \(\frac{AD}{DB} = \frac{AE}{EC} \Rightarrow \frac{4}{6} = \frac{6}{EC} \Rightarrow EC = 9\).
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