In \(\triangle PQR\), ray PS bisects \(\angle QPR\) and S lies on side QR. If \(PQ = 6\), \(PR = 8\) and \(QS = 3\), then \(SR = \)
A. 3
B. 6
C. 4
D. 2.25
A. 3
B. 6
C. 4
D. 2.25
Best answer
Answer: C. 4
By the property of an angle bisector of a triangle, \(\frac{PQ}{PR} = \frac{QS}{SR} \Rightarrow \frac{6}{8} = \frac{3}{SR} \Rightarrow SR = 4\).
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