From a point on the ground 30 m from the foot of a tower, the angle of elevation of the top of the tower is 60°. The height of the tower is
A. \(10\sqrt{3}\) m
B. \(30\sqrt{3}\) m
C. 30 m
D. \(15\sqrt{3}\) m
A. \(10\sqrt{3}\) m
B. \(30\sqrt{3}\) m
C. 30 m
D. \(15\sqrt{3}\) m
Best answer
Answer: B. \(30\sqrt{3}\) m
\(\tan 60° = \frac{h}{30} \Rightarrow h = 30\sqrt{3}\) m.
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