A vertical pole 6 m high casts a shadow \(6\sqrt{3}\) m long. The angle of elevation of the sun is

A. 60°

B. 45°

C. 90°

D. 30°

Doubtly AI Asked 24 Oct 2026 AI-verified · Oct 2026 ssc 10th Save WhatsApp Report

1 answer

Best answer

Answer: D. 30°

\(\tan\theta = \frac{6}{6\sqrt{3}} = \frac{1}{\sqrt{3}} \Rightarrow \theta = 30°\).

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report

Was this answer helpful?