If \(\sec\theta + \tan\theta = 3\), then \(\sec\theta - \tan\theta = \)
A. 3
B. \(\frac{1}{3}\)
C. \(-3\)
D. \(\frac{2}{3}\)
A. 3
B. \(\frac{1}{3}\)
C. \(-3\)
D. \(\frac{2}{3}\)
Best answer
Answer: B. \(\frac{1}{3}\)
\((\sec\theta + \tan\theta)(\sec\theta - \tan\theta) = \sec^2\theta - \tan^2\theta = 1\), so \(\sec\theta - \tan\theta = \frac{1}{3}\).
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